2x(x+3)=2x^2+2x+6

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Solution for 2x(x+3)=2x^2+2x+6 equation: 



2x(x+3)=2x^2+2x+6

We move all terms to the left:

2x(x+3)-(2x^2+2x+6)=0

We multiply parentheses

2x^2+6x-(2x^2+2x+6)=0

We get rid of parentheses

2x^2-2x^2+6x-2x-6=0

We add all the numbers together, and all the variables

4x-6=0

We move all terms containing x to the left, all other terms to the right

4x=6

x=6/4

x=1+1/2

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